(9x+1)/7=(3x-8)/4

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Solution for (9x+1)/7=(3x-8)/4 equation: 



(9x+1)/7=(3x-8)/4

We move all terms to the left:

(9x+1)/7-((3x-8)/4)=0

We calculate fractions


9x/()+(-((3x-8)*7)/()=0



We calculate terms in parentheses: +(-((3x-8)*7)/(), so:

-((3x-8)*7)/(

We multiply all the terms by the denominator


-((3x-8)*7)



We calculate terms in parentheses: -((3x-8)*7), so:

(3x-8)*7

We multiply parentheses

21x-56

Back to the equation:

-(21x-56)



We get rid of parentheses

-21x+56

Back to the equation:

+(-21x+56)



We get rid of parentheses

9x/()-21x+56=0

We multiply all the terms by the denominator


9x-21x*()+56*()=0

We add all the numbers together, and all the variables

9x-21x*()=0

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