(9x+15)*(3x-9)=x

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Solution for (9x+15)*(3x-9)=x equation:



(9x+15)(3x-9)=x
We move all terms to the left:
(9x+15)(3x-9)-(x)=0
We add all the numbers together, and all the variables
-1x+(9x+15)(3x-9)=0
We multiply parentheses ..
(+27x^2-81x+45x-135)-1x=0
We get rid of parentheses
27x^2-81x+45x-1x-135=0
We add all the numbers together, and all the variables
27x^2-37x-135=0
a = 27; b = -37; c = -135;
Δ = b2-4ac
Δ = -372-4·27·(-135)
Δ = 15949
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-\sqrt{15949}}{2*27}=\frac{37-\sqrt{15949}}{54} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+\sqrt{15949}}{2*27}=\frac{37+\sqrt{15949}}{54} $

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