(9x+15)+(2x+3)X=5

Solution for (9x+15)+(2x+3)X=5 equation:

(9x+15)+(2x+3)x=5

We move all terms to the left:

(9x+15)+(2x+3)x-(5)=0

We multiply parentheses

2x^2+(9x+15)+3x-5=0

We get rid of parentheses

2x^2+9x+3x+15-5=0

We add all the numbers together, and all the variables

2x^2+12x+10=0

a = 2; b = 12; c = +10;
Δ = b2-4ac
Δ = 122-4·2·10
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-8}{2*2}=\frac{-20}{4}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+8}{2*2}=\frac{-4}{4}
=-1
$