(9x+2)/(6x-2)=5x/(2x+1)

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Solution for (9x+2)/(6x-2)=5x/(2x+1) equation: 



(9x+2)/(6x-2)=5x/(2x+1)

We move all terms to the left:

(9x+2)/(6x-2)-(5x/(2x+1))=0



Domain of the equation: (6x-2)!=0

We move all terms containing x to the left, all other terms to the right

6x!=2

x!=2/6

x!=1/3

x∈R





Domain of the equation: (2x+1))!=0

x∈R



We calculate fractions


((9x+2)*(2x+1)))/((6x-2)*(2x+1)))+(-(5x*(6x-2))/((6x-2)*(2x+1)))=0



We calculate terms in parentheses: +((9x+2)*(2x+1)))/((6x-2)*(2x+1)))+(-(5x*(6x-2))/((6x-2)*(2x+1))), so:

(9x+2)*(2x+1)))/((6x-2)*(2x+1)))+(-(5x*(6x-2))/((6x-2)*(2x+1))

We add all the numbers together, and all the variables

(9x+2)*(2x+1)))/((6x-2)*(2x+1)))+(-(5x*(6x-2))/((6x-2)*(2x

We multiply all the terms by the denominator


(9x+2)*(2x+1)))-2*2x*((6x+1))+(-(5x*6x*((6x-2))-2*2x*((6x

Wy multiply elements

-4x^2*(+(9x+2)*(2x+1)))-2*2x*((6x+1))+(-(5x*6x*((6x-2))



We calculate terms in parentheses: -(5x*6x*((6x-2)), so:

5x*6x*((6x-2)

Wy multiply elements

30x^3*(

We do not support expression: x^3

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