(9x+24x+16)(3x+4)=0

Solution for (9x+24x+16)(3x+4)=0 equation:

(9x+24x+16)(3x+4)=0

We add all the numbers together, and all the variables

(33x+16)(3x+4)=0

We multiply parentheses ..

(+99x^2+132x+48x+64)=0

We get rid of parentheses

99x^2+132x+48x+64=0

We add all the numbers together, and all the variables

99x^2+180x+64=0

a = 99; b = 180; c = +64;
Δ = b2-4ac
Δ = 1802-4·99·64
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7056}=84$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(180)-84}{2*99}=\frac{-264}{198}
=-1+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(180)+84}{2*99}=\frac{-96}{198}
=-16/33
$