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(9x+3)(12x-6)=0
We multiply parentheses ..
(+108x^2-54x+36x-18)=0
We get rid of parentheses
108x^2-54x+36x-18=0
We add all the numbers together, and all the variables
108x^2-18x-18=0
a = 108; b = -18; c = -18;
Δ = b2-4ac
Δ = -182-4·108·(-18)
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8100}=90$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-90}{2*108}=\frac{-72}{216} =-1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+90}{2*108}=\frac{108}{216} =1/2 $
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