(9x+3)/4=(4x-3)/5

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Solution for (9x+3)/4=(4x-3)/5 equation: 



(9x+3)/4=(4x-3)/5

We move all terms to the left:

(9x+3)/4-((4x-3)/5)=0

We calculate fractions


9x/()+(-((4x-3)*4)/()=0



We calculate terms in parentheses: +(-((4x-3)*4)/(), so:

-((4x-3)*4)/(

We multiply all the terms by the denominator


-((4x-3)*4)



We calculate terms in parentheses: -((4x-3)*4), so:

(4x-3)*4

We multiply parentheses

16x-12

Back to the equation:

-(16x-12)



We get rid of parentheses

-16x+12

Back to the equation:

+(-16x+12)



We get rid of parentheses

9x/()-16x+12=0

We multiply all the terms by the denominator


9x-16x*()+12*()=0

We add all the numbers together, and all the variables

9x-16x*()=0

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