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(9x+3)/4=(4x-3)/5
We move all terms to the left:
(9x+3)/4-((4x-3)/5)=0
We calculate fractions
9x/()+(-((4x-3)*4)/()=0
We calculate terms in parentheses: +(-((4x-3)*4)/(), so:We get rid of parentheses
-((4x-3)*4)/(
We multiply all the terms by the denominator
-((4x-3)*4)
We calculate terms in parentheses: -((4x-3)*4), so:We get rid of parentheses
(4x-3)*4
We multiply parentheses
16x-12
Back to the equation:
-(16x-12)
-16x+12
Back to the equation:
+(-16x+12)
9x/()-16x+12=0
We multiply all the terms by the denominator
9x-16x*()+12*()=0
We add all the numbers together, and all the variables
9x-16x*()=0
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