(9x+4)(x+1)=(3x-2)(3x-2)

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Solution for (9x+4)(x+1)=(3x-2)(3x-2) equation: 



(9x+4)(x+1)=(3x-2)(3x-2)

We move all terms to the left:

(9x+4)(x+1)-((3x-2)(3x-2))=0

We multiply parentheses ..

(+9x^2+9x+4x+4)-((3x-2)(3x-2))=0



We calculate terms in parentheses: -((3x-2)(3x-2)), so:

(3x-2)(3x-2)

We multiply parentheses ..

(+9x^2-6x-6x+4)

We get rid of parentheses

9x^2-6x-6x+4

We add all the numbers together, and all the variables

9x^2-12x+4

Back to the equation:

-(9x^2-12x+4)



We get rid of parentheses

9x^2-9x^2+9x+4x+12x+4-4=0

We add all the numbers together, and all the variables

25x=0

x=0/25

x=0

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