(9x+47)-(6x+58)=120

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Solution for (9x+47)-(6x+58)=120 equation: 



(9x+47)-(6x+58)=120

We move all terms to the left:

(9x+47)-(6x+58)-(120)=0

We get rid of parentheses

9x-6x+47-58-120=0

We add all the numbers together, and all the variables

3x-131=0

We move all terms containing x to the left, all other terms to the right

3x=131

x=131/3

x=43+2/3

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