(9x+5)+(9x+5)+(11x+4)+(11x+4)=258

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Solution for (9x+5)+(9x+5)+(11x+4)+(11x+4)=258 equation: 



(9x+5)+(9x+5)+(11x+4)+(11x+4)=258

We move all terms to the left:

(9x+5)+(9x+5)+(11x+4)+(11x+4)-(258)=0

We get rid of parentheses

9x+9x+11x+11x+5+5+4+4-258=0

We add all the numbers together, and all the variables

40x-240=0

We move all terms containing x to the left, all other terms to the right

40x=240

x=240/40

x=6

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