(9x+6)+(8x-4)=3

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Solution for (9x+6)+(8x-4)=3 equation: 



(9x+6)+(8x-4)=3

We move all terms to the left:

(9x+6)+(8x-4)-(3)=0

We get rid of parentheses

9x+8x+6-4-3=0

We add all the numbers together, and all the variables

17x-1=0

We move all terms containing x to the left, all other terms to the right

17x=1

x=1/17

x=1/17

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