(9x+6/12)+(8x-4/12)=3

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Solution for (9x+6/12)+(8x-4/12)=3 equation: 



(9x+6/12)+(8x-4/12)=3

We move all terms to the left:

(9x+6/12)+(8x-4/12)-(3)=0

We add all the numbers together, and all the variables

(+9x+6/12)+(+8x-4/12)-3=0

We get rid of parentheses

9x+8x-3+6/12-4/12=0

We multiply all the terms by the denominator


9x*12+8x*12+6-4-3*12=0

We add all the numbers together, and all the variables

9x*12+8x*12-34=0

Wy multiply elements

108x+96x-34=0

We add all the numbers together, and all the variables

204x-34=0

We move all terms containing x to the left, all other terms to the right

204x=34

x=34/204

x=1/6

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