(9x+7)/4=(5x-7)/3

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Solution for (9x+7)/4=(5x-7)/3 equation: 



(9x+7)/4=(5x-7)/3

We move all terms to the left:

(9x+7)/4-((5x-7)/3)=0

We calculate fractions


9x/()+(-((5x-7)*4)/()=0



We calculate terms in parentheses: +(-((5x-7)*4)/(), so:

-((5x-7)*4)/(

We multiply all the terms by the denominator


-((5x-7)*4)



We calculate terms in parentheses: -((5x-7)*4), so:

(5x-7)*4

We multiply parentheses

20x-28

Back to the equation:

-(20x-28)



We get rid of parentheses

-20x+28

Back to the equation:

+(-20x+28)



We get rid of parentheses

9x/()-20x+28=0

We multiply all the terms by the denominator


9x-20x*()+28*()=0

We add all the numbers together, and all the variables

9x-20x*()=0

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