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(9x+72)-4x=(4x+112)-4x
We move all terms to the left:
(9x+72)-4x-((4x+112)-4x)=0
We add all the numbers together, and all the variables
-4x+(9x+72)-((4x+112)-4x)=0
We get rid of parentheses
-4x+9x-((4x+112)-4x)+72=0
We calculate terms in parentheses: -((4x+112)-4x), so:We add all the numbers together, and all the variables
(4x+112)-4x
We add all the numbers together, and all the variables
-4x+(4x+112)
We get rid of parentheses
-4x+4x+112
We add all the numbers together, and all the variables
112
Back to the equation:
-(112)
5x-40=0
We move all terms containing x to the left, all other terms to the right
5x=40
x=40/5
x=8
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