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(9x+8)(7x-5)=28
We move all terms to the left:
(9x+8)(7x-5)-(28)=0
We multiply parentheses ..
(+63x^2-45x+56x-40)-28=0
We get rid of parentheses
63x^2-45x+56x-40-28=0
We add all the numbers together, and all the variables
63x^2+11x-68=0
a = 63; b = 11; c = -68;
Δ = b2-4ac
Δ = 112-4·63·(-68)
Δ = 17257
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{17257}}{2*63}=\frac{-11-\sqrt{17257}}{126} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{17257}}{2*63}=\frac{-11+\sqrt{17257}}{126} $
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