(9x+8)(8x+2)=

Solution for (9x+8)(8x+2)= equation:

(9x+8)(8x+2)=

We move all terms to the left:

(9x+8)(8x+2)-()=0

We add all the numbers together, and all the variables

(9x+8)(8x+2)=0

We multiply parentheses ..

(+72x^2+18x+64x+16)=0

We get rid of parentheses

72x^2+18x+64x+16=0

We add all the numbers together, and all the variables

72x^2+82x+16=0

a = 72; b = 82; c = +16;
Δ = b2-4ac
Δ = 822-4·72·16
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2116}=46$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(82)-46}{2*72}=\frac{-128}{144}
=-8/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(82)+46}{2*72}=\frac{-36}{144}
=-1/4
$