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(9x+9)+(12x-3)=x
We move all terms to the left:
(9x+9)+(12x-3)-(x)=0
We add all the numbers together, and all the variables
-1x+(9x+9)+(12x-3)=0
We get rid of parentheses
-1x+9x+12x+9-3=0
We add all the numbers together, and all the variables
20x+6=0
We move all terms containing x to the left, all other terms to the right
20x=-6
x=-6/20
x=-3/10
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