(9x-11)(3-x)=0

Solution for (9x-11)(3-x)=0 equation:

(9x-11)(3-x)=0

We add all the numbers together, and all the variables

(9x-11)(-1x+3)=0

We multiply parentheses ..

(-9x^2+27x+11x-33)=0

We get rid of parentheses

-9x^2+27x+11x-33=0

We add all the numbers together, and all the variables

-9x^2+38x-33=0

a = -9; b = 38; c = -33;
Δ = b2-4ac
Δ = 382-4·(-9)·(-33)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(38)-16}{2*-9}=\frac{-54}{-18}
=+3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(38)+16}{2*-9}=\frac{-22}{-18}
=1+2/9
$