(9x-16)+(3x+11)=(7x-5)

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Solution for (9x-16)+(3x+11)=(7x-5) equation: 



(9x-16)+(3x+11)=(7x-5)

We move all terms to the left:

(9x-16)+(3x+11)-((7x-5))=0

We get rid of parentheses

9x+3x-((7x-5))-16+11=0



We calculate terms in parentheses: -((7x-5)), so:

(7x-5)

We get rid of parentheses

7x-5

Back to the equation:

-(7x-5)



We add all the numbers together, and all the variables

12x-(7x-5)-5=0

We get rid of parentheses

12x-7x+5-5=0

We add all the numbers together, and all the variables

5x=0

x=0/5

x=0

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