(9x-19)+(7x+3)+128+111+5x+8=720

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Solution for (9x-19)+(7x+3)+128+111+5x+8=720 equation: 



(9x-19)+(7x+3)+128+111+5x+8=720

We move all terms to the left:

(9x-19)+(7x+3)+128+111+5x+8-(720)=0

We add all the numbers together, and all the variables

5x+(9x-19)+(7x+3)-473=0

We get rid of parentheses

5x+9x+7x-19+3-473=0

We add all the numbers together, and all the variables

21x-489=0

We move all terms containing x to the left, all other terms to the right

21x=489

x=489/21

x=23+2/7

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