(9x-19)=(2x+5)+(3x+16)

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Solution for (9x-19)=(2x+5)+(3x+16) equation: 



(9x-19)=(2x+5)+(3x+16)

We move all terms to the left:

(9x-19)-((2x+5)+(3x+16))=0

We get rid of parentheses

9x-((2x+5)+(3x+16))-19=0



We calculate terms in parentheses: -((2x+5)+(3x+16)), so:

(2x+5)+(3x+16)

We get rid of parentheses

2x+3x+5+16

We add all the numbers together, and all the variables

5x+21

Back to the equation:

-(5x+21)



We get rid of parentheses

9x-5x-21-19=0

We add all the numbers together, and all the variables

4x-40=0

We move all terms containing x to the left, all other terms to the right

4x=40

x=40/4

x=10

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