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(9x-1=5x+19)
We move all terms to the left:
(9x-1-(5x+19))=0
We calculate terms in parentheses: +(9x-1-(5x+19)), so:We get rid of parentheses
9x-1-(5x+19)
determiningTheFunctionDomain 9x-(5x+19)-1
We get rid of parentheses
9x-5x-19-1
We add all the numbers together, and all the variables
4x-20
Back to the equation:
+(4x-20)
4x-20=0
We move all terms containing x to the left, all other terms to the right
4x=20
x=20/4
x=5
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