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(9x-2)(x-4)=0
We multiply parentheses ..
(+9x^2-36x-2x+8)=0
We get rid of parentheses
9x^2-36x-2x+8=0
We add all the numbers together, and all the variables
9x^2-38x+8=0
a = 9; b = -38; c = +8;
Δ = b2-4ac
Δ = -382-4·9·8
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-38)-34}{2*9}=\frac{4}{18} =2/9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-38)+34}{2*9}=\frac{72}{18} =4 $
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