(9x-2)/3=(2x-7)/7

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Solution for (9x-2)/3=(2x-7)/7 equation:



(9x-2)/3=(2x-7)/7
We move all terms to the left:
(9x-2)/3-((2x-7)/7)=0
We calculate fractions
9x/()+(-((2x-7)*3)/()=0
We calculate terms in parentheses: +(-((2x-7)*3)/(), so:
-((2x-7)*3)/(
We multiply all the terms by the denominator
-((2x-7)*3)
We calculate terms in parentheses: -((2x-7)*3), so:
(2x-7)*3
We multiply parentheses
6x-21
Back to the equation:
-(6x-21)
We get rid of parentheses
-6x+21
Back to the equation:
+(-6x+21)
We get rid of parentheses
9x/()-6x+21=0
We multiply all the terms by the denominator
9x-6x*()+21*()=0
We add all the numbers together, and all the variables
9x-6x*()=0

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