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(9x-20)+(2x+12)+(56)=180
We move all terms to the left:
(9x-20)+(2x+12)+(56)-(180)=0
We add all the numbers together, and all the variables
(9x-20)+(2x+12)-124=0
We get rid of parentheses
9x+2x-20+12-124=0
We add all the numbers together, and all the variables
11x-132=0
We move all terms containing x to the left, all other terms to the right
11x=132
x=132/11
x=12
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