(9x-20)+(2x+12)+(56)=180

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Solution for (9x-20)+(2x+12)+(56)=180 equation: 



(9x-20)+(2x+12)+(56)=180

We move all terms to the left:

(9x-20)+(2x+12)+(56)-(180)=0

We add all the numbers together, and all the variables

(9x-20)+(2x+12)-124=0

We get rid of parentheses

9x+2x-20+12-124=0

We add all the numbers together, and all the variables

11x-132=0

We move all terms containing x to the left, all other terms to the right

11x=132

x=132/11

x=12

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