(9x-20)=(5x+28)

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Solution for (9x-20)=(5x+28) equation: 



(9x-20)=(5x+28)

We move all terms to the left:

(9x-20)-((5x+28))=0

We get rid of parentheses

9x-((5x+28))-20=0



We calculate terms in parentheses: -((5x+28)), so:

(5x+28)

We get rid of parentheses

5x+28

Back to the equation:

-(5x+28)



We get rid of parentheses

9x-5x-28-20=0

We add all the numbers together, and all the variables

4x-48=0

We move all terms containing x to the left, all other terms to the right

4x=48

x=48/4

x=12

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