(9x-26)+(2x-12)=(4x+43)

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Solution for (9x-26)+(2x-12)=(4x+43) equation: 



(9x-26)+(2x-12)=(4x+43)

We move all terms to the left:

(9x-26)+(2x-12)-((4x+43))=0

We get rid of parentheses

9x+2x-((4x+43))-26-12=0



We calculate terms in parentheses: -((4x+43)), so:

(4x+43)

We get rid of parentheses

4x+43

Back to the equation:

-(4x+43)



We add all the numbers together, and all the variables

11x-(4x+43)-38=0

We get rid of parentheses

11x-4x-43-38=0

We add all the numbers together, and all the variables

7x-81=0

We move all terms containing x to the left, all other terms to the right

7x=81

x=81/7

x=11+4/7

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