(9x-27)/6=(3x+15)/10

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Solution for (9x-27)/6=(3x+15)/10 equation:



(9x-27)/6=(3x+15)/10
We move all terms to the left:
(9x-27)/6-((3x+15)/10)=0
We calculate fractions
9x/()+(-((3x+15)*6)/()=0
We calculate terms in parentheses: +(-((3x+15)*6)/(), so:
-((3x+15)*6)/(
We multiply all the terms by the denominator
-((3x+15)*6)
We calculate terms in parentheses: -((3x+15)*6), so:
(3x+15)*6
We multiply parentheses
18x+90
Back to the equation:
-(18x+90)
We get rid of parentheses
-18x-90
Back to the equation:
+(-18x-90)
We get rid of parentheses
9x/()-18x-90=0
We multiply all the terms by the denominator
9x-18x*()-90*()=0
We add all the numbers together, and all the variables
9x-18x*()=0

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