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(9x-3)(2x+4)=0
We multiply parentheses ..
(+18x^2+36x-6x-12)=0
We get rid of parentheses
18x^2+36x-6x-12=0
We add all the numbers together, and all the variables
18x^2+30x-12=0
a = 18; b = 30; c = -12;
Δ = b2-4ac
Δ = 302-4·18·(-12)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-42}{2*18}=\frac{-72}{36} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+42}{2*18}=\frac{12}{36} =1/3 $
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