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(9x-3)+(3x+21)=12x+18
We move all terms to the left:
(9x-3)+(3x+21)-(12x+18)=0
We get rid of parentheses
9x+3x-12x-3+21-18=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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