(9x-3)+(5x+5)+2(7x-15)=168

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Solution for (9x-3)+(5x+5)+2(7x-15)=168 equation: 



(9x-3)+(5x+5)+2(7x-15)=168

We move all terms to the left:

(9x-3)+(5x+5)+2(7x-15)-(168)=0

We multiply parentheses

(9x-3)+(5x+5)+14x-30-168=0

We get rid of parentheses

9x+5x+14x-3+5-30-168=0

We add all the numbers together, and all the variables

28x-196=0

We move all terms containing x to the left, all other terms to the right

28x=196

x=196/28

x=7

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