(9x-3)/3=(4x-3)/7

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Solution for (9x-3)/3=(4x-3)/7 equation: 



(9x-3)/3=(4x-3)/7

We move all terms to the left:

(9x-3)/3-((4x-3)/7)=0

We calculate fractions


9x/()+(-((4x-3)*3)/()=0



We calculate terms in parentheses: +(-((4x-3)*3)/(), so:

-((4x-3)*3)/(

We multiply all the terms by the denominator


-((4x-3)*3)



We calculate terms in parentheses: -((4x-3)*3), so:

(4x-3)*3

We multiply parentheses

12x-9

Back to the equation:

-(12x-9)



We get rid of parentheses

-12x+9

Back to the equation:

+(-12x+9)



We get rid of parentheses

9x/()-12x+9=0

We multiply all the terms by the denominator


9x-12x*()+9*()=0

We add all the numbers together, and all the variables

9x-12x*()=0

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