(9x-3)=(3x+15)

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Solution for (9x-3)=(3x+15) equation: 



(9x-3)=(3x+15)

We move all terms to the left:

(9x-3)-((3x+15))=0

We get rid of parentheses

9x-((3x+15))-3=0



We calculate terms in parentheses: -((3x+15)), so:

(3x+15)

We get rid of parentheses

3x+15

Back to the equation:

-(3x+15)



We get rid of parentheses

9x-3x-15-3=0

We add all the numbers together, and all the variables

6x-18=0

We move all terms containing x to the left, all other terms to the right

6x=18

x=18/6

x=3

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