(9x-39)=47+(3x+10)

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Solution for (9x-39)=47+(3x+10) equation: 



(9x-39)=47+(3x+10)

We move all terms to the left:

(9x-39)-(47+(3x+10))=0

We get rid of parentheses

9x-(47+(3x+10))-39=0



We calculate terms in parentheses: -(47+(3x+10)), so:

47+(3x+10)

determiningTheFunctionDomain
(3x+10)+47

We get rid of parentheses

3x+10+47

We add all the numbers together, and all the variables

3x+57

Back to the equation:

-(3x+57)



We get rid of parentheses

9x-3x-57-39=0

We add all the numbers together, and all the variables

6x-96=0

We move all terms containing x to the left, all other terms to the right

6x=96

x=96/6

x=16

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