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(9x-4)(7x+6)=0
We multiply parentheses ..
(+63x^2+54x-28x-24)=0
We get rid of parentheses
63x^2+54x-28x-24=0
We add all the numbers together, and all the variables
63x^2+26x-24=0
a = 63; b = 26; c = -24;
Δ = b2-4ac
Δ = 262-4·63·(-24)
Δ = 6724
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6724}=82$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-82}{2*63}=\frac{-108}{126} =-6/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+82}{2*63}=\frac{56}{126} =4/9 $
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