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(9x-4)(9x+7)=0
We multiply parentheses ..
(+81x^2+63x-36x-28)=0
We get rid of parentheses
81x^2+63x-36x-28=0
We add all the numbers together, and all the variables
81x^2+27x-28=0
a = 81; b = 27; c = -28;
Δ = b2-4ac
Δ = 272-4·81·(-28)
Δ = 9801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9801}=99$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-99}{2*81}=\frac{-126}{162} =-7/9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+99}{2*81}=\frac{72}{162} =4/9 $
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