(9x-4)/5=(7x+2)/4

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Solution for (9x-4)/5=(7x+2)/4 equation: 



(9x-4)/5=(7x+2)/4

We move all terms to the left:

(9x-4)/5-((7x+2)/4)=0

We calculate fractions


9x/()+(-((7x+2)*5)/()=0



We calculate terms in parentheses: +(-((7x+2)*5)/(), so:

-((7x+2)*5)/(

We multiply all the terms by the denominator


-((7x+2)*5)



We calculate terms in parentheses: -((7x+2)*5), so:

(7x+2)*5

We multiply parentheses

35x+10

Back to the equation:

-(35x+10)



We get rid of parentheses

-35x-10

Back to the equation:

+(-35x-10)



We get rid of parentheses

9x/()-35x-10=0

We multiply all the terms by the denominator


9x-35x*()-10*()=0

We add all the numbers together, and all the variables

9x-35x*()=0

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