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(9x-5)(2x+7)=0
We multiply parentheses ..
(+18x^2+63x-10x-35)=0
We get rid of parentheses
18x^2+63x-10x-35=0
We add all the numbers together, and all the variables
18x^2+53x-35=0
a = 18; b = 53; c = -35;
Δ = b2-4ac
Δ = 532-4·18·(-35)
Δ = 5329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5329}=73$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(53)-73}{2*18}=\frac{-126}{36} =-3+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(53)+73}{2*18}=\frac{20}{36} =5/9 $
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