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(9x-5)(3x+16)=0
We multiply parentheses ..
(+27x^2+144x-15x-80)=0
We get rid of parentheses
27x^2+144x-15x-80=0
We add all the numbers together, and all the variables
27x^2+129x-80=0
a = 27; b = 129; c = -80;
Δ = b2-4ac
Δ = 1292-4·27·(-80)
Δ = 25281
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25281}=159$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(129)-159}{2*27}=\frac{-288}{54} =-5+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(129)+159}{2*27}=\frac{30}{54} =5/9 $
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