(9x-5)(7x+1)=0

Solution for (9x-5)(7x+1)=0 equation:

(9x-5)(7x+1)=0

We multiply parentheses ..

(+63x^2+9x-35x-5)=0

We get rid of parentheses

63x^2+9x-35x-5=0

We add all the numbers together, and all the variables

63x^2-26x-5=0

a = 63; b = -26; c = -5;
Δ = b2-4ac
Δ = -262-4·63·(-5)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-44}{2*63}=\frac{-18}{126}
=-1/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+44}{2*63}=\frac{70}{126}
=5/9
$