(9x-5)3x-10(9x-5)=(9x-5)(3x-10)

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Solution for (9x-5)3x-10(9x-5)=(9x-5)(3x-10) equation: 



(9x-5)3x-10(9x-5)=(9x-5)(3x-10)

We move all terms to the left:

(9x-5)3x-10(9x-5)-((9x-5)(3x-10))=0

We multiply parentheses

27x^2-15x-90x-((9x-5)(3x-10))+50=0

We multiply parentheses ..

27x^2-((+27x^2-90x-15x+50))-15x-90x+50=0



We calculate terms in parentheses: -((+27x^2-90x-15x+50)), so:

(+27x^2-90x-15x+50)

We get rid of parentheses

27x^2-90x-15x+50

We add all the numbers together, and all the variables

27x^2-105x+50

Back to the equation:

-(27x^2-105x+50)



We add all the numbers together, and all the variables

27x^2-105x-(27x^2-105x+50)+50=0

We get rid of parentheses

27x^2-27x^2-105x+105x-50+50=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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