(9x-6)+(3x+18)=180

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Solution for (9x-6)+(3x+18)=180 equation: 



(9x-6)+(3x+18)=180

We move all terms to the left:

(9x-6)+(3x+18)-(180)=0

We get rid of parentheses

9x+3x-6+18-180=0

We add all the numbers together, and all the variables

12x-168=0

We move all terms containing x to the left, all other terms to the right

12x=168

x=168/12

x=14

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