(9x-6)+58=(16x-4)

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Solution for (9x-6)+58=(16x-4) equation: 



(9x-6)+58=(16x-4)

We move all terms to the left:

(9x-6)+58-((16x-4))=0

We get rid of parentheses

9x-((16x-4))-6+58=0



We calculate terms in parentheses: -((16x-4)), so:

(16x-4)

We get rid of parentheses

16x-4

Back to the equation:

-(16x-4)



We add all the numbers together, and all the variables

9x-(16x-4)+52=0

We get rid of parentheses

9x-16x+4+52=0

We add all the numbers together, and all the variables

-7x+56=0

We move all terms containing x to the left, all other terms to the right

-7x=-56

x=-56/-7

x=+8

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