(9x-9)(8x+7)=0

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Solution for (9x-9)(8x+7)=0 equation:



(9x-9)(8x+7)=0
We multiply parentheses ..
(+72x^2+63x-72x-63)=0
We get rid of parentheses
72x^2+63x-72x-63=0
We add all the numbers together, and all the variables
72x^2-9x-63=0
a = 72; b = -9; c = -63;
Δ = b2-4ac
Δ = -92-4·72·(-63)
Δ = 18225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{18225}=135$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-135}{2*72}=\frac{-126}{144} =-7/8 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+135}{2*72}=\frac{144}{144} =1 $

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