(9x-9)/6=(3x+21)/10

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Solution for (9x-9)/6=(3x+21)/10 equation: 



(9x-9)/6=(3x+21)/10

We move all terms to the left:

(9x-9)/6-((3x+21)/10)=0

We calculate fractions


9x/()+(-((3x+21)*6)/()=0



We calculate terms in parentheses: +(-((3x+21)*6)/(), so:

-((3x+21)*6)/(

We multiply all the terms by the denominator


-((3x+21)*6)



We calculate terms in parentheses: -((3x+21)*6), so:

(3x+21)*6

We multiply parentheses

18x+126

Back to the equation:

-(18x+126)



We get rid of parentheses

-18x-126

Back to the equation:

+(-18x-126)



We get rid of parentheses

9x/()-18x-126=0

We multiply all the terms by the denominator


9x-18x*()-126*()=0

We add all the numbers together, and all the variables

9x-18x*()=0

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