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(9x/2x)=5-8x/5x
We move all terms to the left:
(9x/2x)-(5-8x/5x)=0
Domain of the equation: 2x)!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+9x/2x)-(-8x/5x+5)=0
We get rid of parentheses
9x/2x+8x/5x-5=0
We calculate fractions
45x^2/10x^2+16x^2/10x^2-5=0
We multiply all the terms by the denominator
45x^2+16x^2-5*10x^2=0
We add all the numbers together, and all the variables
61x^2-5*10x^2=0
Wy multiply elements
61x^2-50x^2=0
We add all the numbers together, and all the variables
11x^2=0
a = 11; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·11·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{22}=0$
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