(9x/5)+32=3x

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Solution for (9x/5)+32=3x equation: 



(9x/5)+32=3x

We move all terms to the left:

(9x/5)+32-(3x)=0

We add all the numbers together, and all the variables

(+9x/5)-3x+32=0

We add all the numbers together, and all the variables

-3x+(+9x/5)+32=0

We get rid of parentheses

-3x+9x/5+32=0

We multiply all the terms by the denominator


-3x*5+9x+32*5=0

We add all the numbers together, and all the variables

9x-3x*5+160=0

Wy multiply elements

9x-15x+160=0

We add all the numbers together, and all the variables

-6x+160=0

We move all terms containing x to the left, all other terms to the right

-6x=-160

x=-160/-6

x=26+2/3

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