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(9x=+5)-(x-5)=
We move all terms to the left:
(9x-(+5)-(x-5))=0
We add all the numbers together, and all the variables
(9x-5-(x-5))=0
We calculate terms in parentheses: +(9x-5-(x-5)), so:x=0/8
9x-5-(x-5)
determiningTheFunctionDomain 9x-(x-5)-5
We get rid of parentheses
9x-x+5-5
We add all the numbers together, and all the variables
8x
Back to the equation:
+(8x)
x=0
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