(9y+2/2)+(4y+5/6)=7

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Solution for (9y+2/2)+(4y+5/6)=7 equation:



(9y+2/2)+(4y+5/6)=7
We move all terms to the left:
(9y+2/2)+(4y+5/6)-(7)=0
We add all the numbers together, and all the variables
(9y+1)+(+4y+5/6)-7=0
We get rid of parentheses
9y+4y+1-7+5/6=0
We multiply all the terms by the denominator
9y*6+4y*6+5+1*6-7*6=0
We add all the numbers together, and all the variables
9y*6+4y*6-31=0
Wy multiply elements
54y+24y-31=0
We add all the numbers together, and all the variables
78y-31=0
We move all terms containing y to the left, all other terms to the right
78y=31
y=31/78
y=31/78

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