(9y+7)/3=(y+1)/6=22

Solution for (9y+7)/3=(y+1)/6=22 equation:

(9y+7)/3=(y+1)/6=22

We move all terms to the left:

(9y+7)/3-((y+1)/6)=0

We calculate fractions


9y/()+(-((y+1)*3)/()=0


We calculate terms in parentheses: +(-((y+1)*3)/(), so:

-((y+1)*3)/(

We multiply all the terms by the denominator


-((y+1)*3)


We calculate terms in parentheses: -((y+1)*3), so:

(y+1)*3

We multiply parentheses

3y+3

Back to the equation:

-(3y+3)


We get rid of parentheses

-3y-3

Back to the equation:

+(-3y-3)


We get rid of parentheses

9y/()-3y-3=0

We multiply all the terms by the denominator


9y-3y*()-3*()=0

We add all the numbers together, and all the variables

9y-3y*()=0